Since Gα is not just a subset of G but in fact a subgroup, the action of G on Ω induces an action of Gα on Ω.
Definition The orbits of Gα on Ω (by this induced action) are called suborbits, their sizes are called subdegrees and the rank is how many there are.
Recall the orbit/stabilizer theorem:
- αG={αg∈Ω|g∈G}
- Gα={g∈G|αg=α}
- Since αg=αg′ iff gg′−1∈Gα iff Gαg=Gαg′ the bijection αg↦Gαg is well defined, it also respects the group action.
Suborbits of Gα are the orbits βGα which are thus in bijection with the double cosets GαgGα.
We call these (Gα,Gα)-double cosets and they partition the group. The size of a double coset divided by |Gα| gives the subdegree (similar to Lagrange's theorem).
Lemma The rank of the action of G is 1|G|∑g∈G|fix(g)|2.
proof: Apply Burnside's lemma to the action of Gα on Ω to get |Ω||G|∑g∈Gα|fix(g)| since |Gα|=|G||Ω| now sum over all α to get 1|G|∑α∈Ω∑g∈Gα|fix(g)|=1|G|∑g∈G∑α∈fix(g)|fix(g)|.
Definition Let α,β∈Ω. The 2-point stabilizer Gα,β is Gα∩Gβ.
Definition The pointwise stabilizer of a set of points Γ⊆Ω, G(Γ) is bigcapγ∈ΓGγ.
Definition The setwise stabilizer GΓ={g∈G|Γg=Γ}.
Lemma Given β∈Ω the subdegree corresponding to β is |Gα:Gα,β|.
proof: In the action of Gα on the suborbit βGα the stab. of β is Gα∩Gβ. The result follows from orb/stab theorem.
Definition If Gα=1 the action is regular and has rank |Ω|
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