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Thursday, 7 February 2013

Suborbits and double-cosets

Throughout we will assume that G acts transitively on Ω. The idea motivating this section is that since each orbit is conjugate, what freedom remains when we pick some fixed α and consider Gα (The stabilizer of α)?

Since Gα is not just a subset of G but in fact a subgroup, the action of G on Ω induces an action of Gα on Ω.

Definition The orbits of Gα on Ω (by this induced action) are called suborbits, their sizes are called subdegrees and the rank is how many there are.


Recall the orbit/stabilizer theorem:
  • αG={αgΩ|gG}
  • Gα={gG|αg=α}
  • Since αg=αg iff gg1Gα iff Gαg=Gαg the bijection αgGαg is well defined, it also respects the group action.
By transitivity every element βΩ can be written as αg for some g, in fact {β}=αGαg so elements of Ω are in bijection with the right cosets {Gαg|gG}.

Suborbits of Gα are the orbits βGα which are thus in bijection with the double cosets GαgGα.

We call these (Gα,Gα)-double cosets and they partition the group. The size of a double coset divided by |Gα| gives the subdegree (similar to Lagrange's theorem).

Lemma The rank of the action of G is 1|G|gG|fix(g)|2.
proof: Apply Burnside's lemma to the action of Gα on Ω to get |Ω||G|gGα|fix(g)| since |Gα|=|G||Ω| now sum over all α to get 1|G|αΩgGα|fix(g)|=1|G|gGαfix(g)|fix(g)|.

Definition Let α,βΩ. The 2-point stabilizer Gα,β is GαGβ.
Definition The pointwise stabilizer of a set of points ΓΩ, G(Γ) is bigcapγΓGγ.
Definition The setwise stabilizer GΓ={gG|Γg=Γ}.

Lemma Given βΩ the subdegree corresponding to β is |Gα:Gα,β|.
proof: In the action of Gα on the suborbit βGα the stab. of β is GαGβ. The result follows from orb/stab theorem.

Definition If Gα=1 the action is regular and has rank |Ω|

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