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Saturday, 19 January 2013

Noether4 (unfinished)

Lemma (Lattice isomorphism theorem) Let α:GH be some group homomorphism. There is a natural bijection between the (normal) subgroups of G that contain ker(α) and the subgroups of im(α).
proof: For KG let Kα={α(k)H|kK} (note this is a group) and for Mim(α) let M={gG|α(g)M} this too is a group. Clearly (M)α={α(g)G|α(g)M}=M since every element of M is in the image of α. Now (Kα)K easily by definition and the reverse inclusion comes down to the something about kernel. As for the inclusions unproved.

Theorem (Noether4). Let G be a group and NG. There is a natural bijection between the lattice of subgroups of G that contain N and the lattice of subgroups of G/N. The bijection preserves relations "subgroup", "normal subgroup" and properness.
proof: Let H be a subgroup of G which contains N i.e. N is also a subgroup of it then by Noether3 N is normal in H too so H/N is well defined homomorphism. Now apply lattice isomorphism.

Corollary: If BG/N then K,BK/N.

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